Question

Which line is a graph of the equation: 2x + 5y = –10? Number graph ranging from negative five to five on the x axis and negative six to two on the y axis. Four lines are drawn in blue on the graph. Lines a and c have a positive slope and are parallel to each other. Lines b and d have a negative slope and are parallel to each other. Lines a and b intersect at (zero, two), and lines c and d intersect at (zero, negative two). A. line a B. line b C. line c D. line d

Answer 1

Answer:the answer is line D

Step-by-step explanation:took the test and got it right

Answer 2

First we find the slope of the given line by using slope intercept form.

Converting the equation into slope intercept form

`5y=-2x-10`

Divide both side by 5 we get

`y==-(2)/(5)-2`

On comparing with
`y=mx+c`

We get slope
`m=-(2)/(5)`

as the slope of line is negative therefore the line will either "b" or "d"

As line "b" pass from (0,2)

On putting it in given equation we get

`2(0)+5(2)=10`

Which is not equL to RHS of the line

Therefore b is not the given line

Now putting point (0,-2)

We get
`0+5(-2)=-10`

Satisfy the equation and line "d" pass from it

There the give equationis of line "d"