Find a so that the point (-1,4) is on the graph of f(x)=ax^2+3

Jordiburgos asked Dec 28, 2023

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Jordiburgos asked Dec 28, 2023

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27 votes

f(x)=ax^2+3
4=a(-1^2)+3
4=a(1)+3
a=4-3
a=1

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