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Calculate the energy of a photon of electromagnetic radiation whose frequency is 2.81×1014 s?1

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Answer : The energy of a photon is
18.619* 10^(-20)J.

Solution : Given,

Frequency of a photon =
2.81* 10^(14)s^-

Planck' constant =
6.626* 10^(-34)Js

Formula used :


E=h\\u

where,

E = Energy of a photon

h = Planck's constant


\\u = Frequency of a photon

Now put all the given values in above formula, we get


E=(6.626* 10^(-34)Js)* (2.81* 10^(14)s^-)
=18.619* 10^(-20)J

Thus, the energy of a photon is
18.619* 10^(-20)J.

User ArunGJ
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