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A 5 N force pushes on the right side of a box . At the same time a 10 N force pushes in the left side of the box what happens to the box ?

User SavageGoat
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2 Answers

5 votes

As long as the friction force under the box is less than 5N, it'll accelerate to the right.

User Barrymc
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2 votes

The box will move 5n left because:

10-5=5

Then, you take the side that has the biggest number. In this case, 10n left > 5n right

User Nirajan Mahara
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