Question

While Bob is demonstrating the gravitational force on falling objects to his class, he drops an 1.0 lb bag of feathers from the top of the science building. Determine the distance the bag has traveled after falling for 1.5 seconds assuming it has reach free fall and given the gravitational acceleration of 9.8 m/sec2.

Answer 1

The 1.0 lb bag of feathers has traveled approximately 11.025 meters after falling for 1.5 seconds, assuming it is in free fall and subject to Earth's gravitational acceleration of 9.8 m/s².

Step-by-step explanation:

To determine the distance the 1.0 lb bag of feathers has traveled after falling for 1.5 seconds, assuming it has reached free fall and is only affected by gravitational acceleration, we can use the formula for the distance covered by an object in free fall:

d = ½ * g * t²,

where g is the acceleration due to gravity (9.8 m/s²) and t is the time in seconds.

Plugging in the values:

d = ½ * 9.8 m/s² * (1.5 s)²

d = ½ * 9.8 * 2.25

d = ½ * 22.05

d = 11.025 meters

Therefore, the bag of feathers has traveled approximately 11.025 meters after falling for 1.5 seconds.

Answer 2

In the experiment of free fall bob released a bag of mass 1 lb

so here we can say that initial speed of the bag is Zero

time taken by the bag to free fall is given as

t = 1.5 s

also the acceleration of free fall is given as

a = 9.8 m/s^2

now we will use kinematics equation here for finding the distance of free fall

`d = v_i * t + (1)/(2) at^2`

`d = 0 + (1)/(2)*9.8* 1.5^2`

`d = 4.9 * 2.25`

`d = 11.025 m`

so the bag will fall down by total distance of 11.025 m from its initial released position.