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Solve for x for 0 ≤ x < 2 π . tanxsinx - tanx = 0

User Tolsto
by
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1 Answer

3 votes

Let's solve this

We need to accept solutions in the given interval 0 ≤ x < 2 pi

tanx * sinx - tanx = 0 First we pull out tanx in front of the bracket and get

=> tanx ( sinx - 1 ) = 0 now we interpret product and get

tanx = 0 or sinx - 1 = 0

When tanx = 0 => angle is x1=0

sinx - 1 = 0 => sinx = 1 When sinx = 1 then angle is x2= pi/2

The solutions are inside given interval 0 ≤ x < 2 pi and we accept it.

The correct answer is (x1, x2) = (0, pi/2)

Good luck!!!

User Michael Millar
by
4.8k points
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