Answer:
x = 1; y = 1; z = 0
Explanation:
First problem:
First equation minus second equation: 3y + 2z = 3 Eq. A
Second equation plus third equation: 2y + 4z = 2 Eq. B
-2 times Eq. A plus Eq. B: -4y = -4
y = 1
Substitute y = 1 in Eq. A: 3 + 2z = 3
2z = 0
z = 0
Substitute z = 0 and y = 1 in original first equation:
-2x + 2 + 0 = 0
-2x = -2
x = 1
Answer: x = 1; y = 1; z = 0