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use the fact that there are 2pi radians in each circle to find another angle, smaller than 2pi, that is equivalent to 17pi/6. Show steps please

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we are given angle as


\theta=(17\pi)/(6)

we can write it as


\theta=(12\pi+5\pi)/(6)

now, we can break it


\theta=(12\pi)/(6)+(5\pi)/(6)

On simplifying


\theta=2\pi +(5\pi)/(6)

we know all angles repeats itself after 2pi

so,


2\pi + \theta= \theta

so, we get


\theta=(5\pi)/(6)...............Answer

User Daemon
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