Question

What is the midpoint of AB?

Answer 1

The formula of a midpoint:

`\left((x_A+x_B)/(2),\ (y_A+y_B)/(2)\right)`

We have

`A(-2,\ 5),\ B(3,\ -3)`

Substitute:

`(-2+3)/(2)=(1)/(2)=0.5\\\\(5+(-3))/(2)=(2)/(2)=1`

Answer: (0.5, 1).

Answer 2

The midpoint of AB is (0.5,1).

Explanation:

From the given graph it is clear that the vertices of the triangle ABC are A(-2,5), B(3,-3) and C(-4,-1).

If end points of a line segment are
`(x_1,y_1)` and
`(x_2,y_2)`, then the midpoint of that segment is

`Midpoint=((x_1+x_2)/(2),(y_1+y_2)/(2))`

We need to find the midpoint of AB.

`Midpoint=((-2+3)/(2),(5+(-3))/(2))`

`Midpoint=((1)/(2),(5-3)/(2))`

On further simplification we get

`Midpoint=((1)/(2),(2)/(2))`

`Midpoint=(0.5,1)`

Therefore the midpoint of AB is (0.5,1).