Question

Mrs. Robbins was trying to find a matching pair of shoes in her closet this morning. She has 4 blue shoes, 6 black shoes, 2 brown shoes, 2 white shoes, 2 pink shoes, and 6 sparkly shoes. The light bulb in the closet went out so she couldn't see anything. What is the probability she will grab a white shoe, keep it, and grab another white shoe?​

Answer 1

The probability that Mrs. Robbins will grab a white shoe and then another white shoe in the dark is 1/231.

Step-by-step explanation:

The student's question is about calculating the probability of Mrs. Robbins grabbing two white shoes in the dark. Since Mrs. Robbins has 2 white shoes, the probability of her first pick being a white shoe is 2 out of the total number of shoes. The total number of shoes is 4 blue + 6 black + 2 brown + 2 white + 2 pink + 6 sparkly, which equals 22.

Therefore, the probability of the first shoe being white is 2/22 or 1/11. If Mrs. Robbins picks a white shoe and keeps it (without replacement), there will be 1 white shoe left out of a new total of 21 shoes. Thus, the probability of the second shoe being white is 1/21.

To find the overall probability of both events occurring, we multiply the two individual probabilities:
Probability of first white shoe * Probability of second white shoe = (1/11) * (1/21).

The final probability is (1/11) * (1/21) = 1/231. Therefore, the probability that Mrs. Robbins will grab a white shoe and then another white shoe is 1/231.

Answer 2

14 ; three of them are black, 2 are black and leather, 9 are leather

Step-by-step explanation:

i hope this helps