Question

Solve for x in the equation is x^2-4x-9=29

Answer 1

Step 1. Move all terms to one side

`x^2-4x-9-29=0`

Step 2. Simplify
`x^2-4x-9-29` to
`x^2-4x-38`

`x^2-4x-38=0`

Step 3. Use the Quadratic Formula

`x=(4+2√(42) )/(2) ,(4-2√(42) )/(2 )`

Step 4. Simplify solutions

`x = 2 √(42,) 2-√(42)`

Answer 2

Let's solve your equation step-by-step.

`x^(2)`−4x−9=29

Step 1: Subtract 29 from both sides.

`x^(2)`−4x−9−29=29−29

`x^(2)`−4x−38=0

Step 2: Use quadratic formula with a=1, b=-4, c=-38.

`x=\frac{-b+-\sqrt{b^(2) -4ac} }{2a}`

`x=\frac{-(-4)+-\sqrt({-4})^(2) -4(1)(-38)}{2(1)}`

`x=(4-+√(168))/(2)`

Answer:

`x=2+√(42)` or x = -2
`√(42)`