Answer:
The correct option is C.
Explanation:
The height of the ball is defined by a parabolic function.
Let the equation of the parabola is

Where, (h,k) is the vertex and a is stretch factor.
The maximum height of the ball is 15 feet in 2.2 seconds. So, the vertex is (2.2, 15).
The equation of the parabola is

The initial height of the ball is 0.




The equation of the parabola is

The function takes 2.2 seconds to reach at maximum height, so after that it will take 2.2 seconds to reach at growth again.

The ball will reach the growth at x=4.4.
The height can not be negative, therefore the value of x lies between 0 to 4.4. The domain of the function is

Therefore option C is correct.