Question

Corbin, an avid skier leaves the horizontal end of a ramp with a velocity of 33.0 m/s and lands 63.0 m from the base the ramp. How high is the end of the ramp from the ground?

Answer 1

Height of ramp = 17.49 m

Step-by-step explanation:

We have equation of motion ,
`s= ut+(1)/(2) at^2`, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Considering horizontal motion of skier

Initial velocity = 33 m/s, Displacement = 63 m, acceleration = 0 and we need to find time taken to reach ground by the skier.

`63= 33t+(1)/(2) *0*t^2\\ \\ t=1.909seconds`

The vertical distance traveled in 1.909 seconds is the height of ramp

Initial velocity = 0 m/s, acceleration = acceleration due to gravity = 9.8
`m/s^2`, time = 1.909 s and we need to find displacement.

`s= 0*1.909+(1)/(2) *9.8*1.909^2\\ \\ s=17.49 m`

So height of ramp = 17.49 m