Question

What is the wavelength of a radio photon from an "am" radio station that broadcasts at 1280 kilohertz and energy

Answer 1

The wavelength, frequency and speed of a photon are related as:

`\lambda=(c)/(f)`

where,
`\lambda` is the wavelength, c is the speed of light because all photons travels with speed of light, c in space, and f is the frequency.

`\Rightarrow\lambda=(3*10^8m/s)/(1280* 10^3s^(-1))=234 m`

Hence, the wavelength of the radio photon is 234 m

Energy of this photon:

`E=hf`

where, h is the Planck's constant.

`E=6.6* 10^(-34) Js* 1280* 10^3s^(-1)=8448 * 10^(-31) J`

Hence, the energy of the radio photon is
`8448 * 10^(-31) J`