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A metal ball of mass 2 kg is supported by a massless inextensible string, 12 cm long. A horizontal force displaces the ball by 30oto the vertical so that the string remains taut. Find:a) the horizontal force.b) the tension in the thread.

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As it is given that 2 kg mass is suspended by 12 cm long thread and then a horizontal force is applied on it so that it remains in equilibrium at 30 degree angle

So here we can use force balance in X and Y directions

now for X direction or horizontal direction we can use


F = Tsin30

for vertical direction similarly we can say


mg = T cos30

so here we first divide the two equations


(F)/(mg) = (sin 30)/(cos 30)


(F)/(mg) = tan 30


F = mg tan30

now plug in all values in the above equation


F = 2 * 9.8 * tan30


F = 11.3 N

Part b)

now in order to find the tension in the thread we can use any above equation


F = T sin30


11.3 = T sin30


T = (11.3)/(sin30)


T = 22.6 N

so tension in the thread will be 22.6 N

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