58.6k views
1 vote
-6g + 3g + 12 > -18

a.
g < 2
b.
g > 2
c.
g < 10
d.
g > 10

a.
g < 2
b.
g > 2
c.
g < 10
d.
g > 10

User Thiri
by
8.3k points

1 Answer

3 votes

First of all, you can sum the two terms involving g on the left hand side:


-6g + 3g + 12 > -18 \iff -3g + 12 > -18

Subtract 12 from both sides:


-3g > -30

Divide both sides by -3: note that since we're dividing by a negative number, we must invert the inequality sign:


g< 10

User Kabindas
by
7.7k points

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