Question

-6g + 3g + 12 > -18

a.
g < 2
b.
g > 2
c.
g < 10
d.
g > 10

a.
g < 2
b.
g > 2
c.
g < 10
d.
g > 10

Answer 1

First of all, you can sum the two terms involving g on the left hand side:

`-6g + 3g + 12 > -18 \iff -3g + 12 > -18`

Subtract 12 from both sides:

`-3g > -30`

Divide both sides by -3: note that since we're dividing by a negative number, we must invert the inequality sign:

`g< 10`