Question

Jim is building a model airplane.The scale is 1 in:40ft.The actual distance of the wingspan is 211 feet.How long will the wings of the model be

Answer 1

Answer: The wings of the model will be 5.275 in

Explanation:

Since we have given that

The scale is 1 in : 40 ft. i.e. Model : Actual.

The actual distance of the wingspan = 211 feet

Let the model of the wing be x

i.e.

`(1)/(40)=(x)/(211)\\\\1* 211=x* 40\\\\x=(211)/(40)\\\\x=5.275 in`

So, the wings of the model will be 5.275 in.

Answer 2

The wings of the model will be 0.4396ft long

Explanation.

We convert the scale
`1in:40ft` so we can obtain the scale in the same units.

We know that,

1 foot =12 inches. This implies that

`1inch=(1)/(12)` ft

`(1)/(12):40` ft

Let us multiplyeach term in the ratio by 12

Tis implies the scale is 1:480

Since 211 is less than 480 we divide to obtain length of

wing of model to be

`(211)/(240)=0.4396`ft