Question

Which exponential function has an initial value of 2?

A) f(x) = 2(3^x)
B) the first picture
C) f(x) = 3(2^x)
D) the last picture

Answer 1

A) f(x) = 2(3^x) is the answer

Answer 2

The correct option is A)
`f(x)=2(3^(x))` has an initial value of 2 .

Explanation:

We need to find the exponential function has an initial value of 2

To check function which has an initial value of 2, we put
`x=0`

Check for A)
`f(x)=2(3^(x))`

Put x=0

`f(0)=2(3^(0))`

`f(0)=2`

so, this is the function has an initial value of 2

Therefore, the correct option is A)
`f(x)=2(3^(x))` has an initial value of 2 .