Question

How many grams of F are in 405 grams of CaF2?

Answer 1

I would say that there is 270 grams left. since its F2 you have three things there.

divide 405 by 3

you will get 135.

but there are 2 F's so multiply that by 2 and you will get 270.

the final answer should be 270 grams left.

Answer 2

Answer: 197 grams

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=`

Given mass = 405 g

Molar mass = 78.07 g/mol

`\text{Number of moles}=(405g)/(78.07g/mol)=5.19moles`

1 mole of
`CaF_2` contains = 2 moles of fluorine

5.19 mole of
`CaF_2` contains =
`(2)/(1)* 5.19=10.38moles` of fluorine

Mass of flourine =
`moles* molar mass=10.38* 19=197g`

Thus 197 grams of F are in 405 grams of
`CaF_2` .