Question

3x+8+2ax≥3ax−4a what is x?

Answer 1

x≥

`- \frac {4 (2 + a)}{3 - a}`
solve the inequality by finding the roots and creating test intervals.

Answer 2

`\text{x}\geq \frac{-4(2+\text{a})}{(3-\text{a})}`

Explanation:

Given: the inequality 3x+8+2ax≥3ax−4a

To Find: value of x

Solution:

in given inequality

`3\text{x}+8+2\text{a}\text{x}\geq 3\text{a}\text{x}-4\text{a}`

`3\text{x}+2\text{a}\text{x}-3\text{a}\text{x}\geq -4\text{a}-8`

`\text{x}(3+2\text{a}-3\text{a})\geq -8-4\text{a}`

`\text{x}(3-\text{a})\geq -8-4\text{a}`

`\text{x}\geq \frac{-8-4\text{a}}{(3-\text{a})}`

`\text{x}\geq \frac{-4(2+\text{a})}{(3-\text{a})}`

therefore value of
`\text{x}\geq \frac{-4(2+\text{a})}{(3-\text{a})}`