Question

How many grams of oxygen is needed to completelt react with of 9.30 of aluminum

Answer 1

Hey there!

Given the reaction:

4 AI + 3O2 ------> 2 AI2O3

4 moles Al --------- 3 moles O2

9.30 moles Al --------- ?? moles O2

9.30 * 3 / 4 => 6.975 moles of O2

Molar mass O2 => 32.0 g

Therefore:

6.975 * 32.0 => 223.3 g of Oxygen

Hope that helps!