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A current of 0.2 A flows through an electric bell having a resistance of 65 ohms. What must be the applied voltage in the circuit?

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Now we know by Ohm's law that


Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.


Introducing the constant of proportionality, the resistance,the Ohm's law can be mathematically represented as


V=I x R


Where V is the voltage measured in volts


I is the current measured in amperes


R is the resistance measured in ohms



Given:


I = 0.2 A


R= 65 ohms


Now substituting the values in Ohm's law we get


V = I x R


V = 0.2 x 65



V = 13 volts


User Jubal
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