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Prove that x+a is a factor of (x+a)^5 + (x+c)^5 + (a-c)^5

User Albertjan
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1 Answer

3 votes


P(x)=(x+a)^5 + (x+c)^5 + (a-c)^5

If
x+a is a factor of
P(x), then
-a is a root of
P(x).

Therefore


(-a+a)^5+(-a+c)^5+(a-c)^5=0\\\\0^5+(-1(a-c))^5+(a-c)^5=0\\\\(-1)^5(a-c)^5+(a-c)^5=0\\\\-(a-c)^5+(a-c)^5=0\\\\0=0

User Benjamin Mesing
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