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Answer question please
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Answer question please

Answer question please-example-1
User Sylvan LE DEUNFF
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1 Answer

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∠EFH = 6y + 14

since HF bisects ∠GFI then ∠GFH = ∠HFI = 2y + 6

hence ∠EFH = ∠EFG + ∠GFH = 4y + 8 + 2y + 6 = 6y + 14


User Lav Vishwakarma
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