Question

A person travels to a destination at a rate of 50m/h and returns the next day at a rate of 40m/h. If the time returning is 1hour more than the time going, how many miles are traveled in all?

Answer 1

the time returning=x h,

the time going=(x-1) h,

s=t*v

s=(x-1)*50,

s=x*40,

(x-1)*50=x*40

x=5h,

s=t*v=5*50=250 miles