Question

Find 3 consecutive odd integers such that the sum of the smallest number and the middle number is 27 less than 3 times the largest number

Answer 1

Let consecutive odd numbers be

x , x+2 , x+4

Smallest number =x

Middle number =x+2

Largest number =x+4

According to condition (x) +(x+2) -27 = 3(x+4)

x+x+2-27= 3(x+4)

2x-25= 3x+12

Subtracting 2x and 12 both sides

2x-25-2x-12=3x+12-2x-12

-37= x this is smallest odd number.

Other two odd numbers are (x+2)= (-37+2)=(-35)

& (x+4)=(-37+4)=(-33)

so three consecutive odd numbers are -37 ,-35 , -33