Question

Little Melinda has nickels and quarters in her bank. She has two

fewer nickels than quarters. She has ​$3.50

in the bank. How many coins of each type does she​ have?
How many quarters does she​ have?

Answer 1

Melinda has 12 quarters and 10 nickels in her bank, totaling $3.50. By setting up and solving equations based on the values of the coins, we were able to determine the exact number of each type of coin.

Step-by-step explanation:

Little Melinda has nickels and quarters in her bank, with two fewer nickels than quarters. The total amount of money she has is $3.50. To determine how many coins of each type she has, we need to set up equations based on the values of the coins and the given conditions.

Let's define:
Q = number of quarters
N = number of nickels
Since each quarter is worth 25 cents and each nickel is worth 5 cents, we have the following equations:

1. N = Q - 2 (since she has two fewer nickels than quarters)
2. (5 × N) + (25 × Q) = 350 cents (because the total amount is $3.50)

Substitute the first equation into the second to find the number of each coin:
5(Q - 2) + 25Q = 350
5Q - 10 + 25Q = 350
30Q - 10 = 350
30Q = 360
Q = 12

Then, substitute Q = 12 into the first equation to find N:
N = 12 - 2
N = 10

Therefore, Melinda has 12 quarters and 10 nickels.

Answer 2

A) N +2 = Q which equals

A) N -Q = -2

B) .05N +.25Q = 3.50 multiplying A) by .25

A) .25N -.25Q = -.5 then adding A) and B)

.30N = 3

Nickels = 10 Quarters = 12

*************DOUBLE CHECK ***************

.05 nickels = $0.50 .25 Quarters = $3.00