Question

Please help!! Chemistry!! Important!! Will mark brainiliest

1. The half-reaction 2MnO2 + H2O + 2e- Mn2O3 is missing
a. electrons
b. OH- ions
c. Mn2+ ions
d. O2- ions

2. The oxidation number of S in SO2−4 is
a. 2
b. +2
c. +4
d. +6

Answer 1

Part 1 :

The option B is correct option.

The half-reaction 2MnO2 + H2O + 2e- Mn2O3 is missing OH- ions.

Step-by-step explanation:

Full equation:

2MnO2 + H2O + 2e- → Mn2O3 + 2OH-

Part 2.

The oxidation number of S in SO2−4 is 0.

Because in ionic compounds sum of oxidation number is equal to charge.

If compound is SO4-2 then option d will correct option.

Because (+6) + (-2 * 4) = -2