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In the diagram abc=adb=90, ad=p and dc=q. Use similar triangles to show that x2=pz

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In the diagram abc=adb=90, ad=p and dc=q. Use similar triangles to show that x2=pz-example-1
User Bluehallu
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1 Answer

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Answer:

By comparing the ratios of sides in similar triangles ΔABC and ΔADB,we can say that
x^(2) =pz

Explanation:

Given that ∠ABC=∠ADC, AD=p and DC=q.

Let us take compare Δ ABC and Δ ADB in the attached file , ∠A is common in both triangles

and given ∠ABC=∠ADB=90°

Hence using AA postulate, ΔABC ≈ ΔADB.

Now we will equate respective side ratios in both triangles.


(AB)/(AC)= (AD)/(AB)=(BD)/(BC)

Since we don't know BD , BC let us take first equality and plugin the variables given in respective sides.


(x)/(z)= (p)/(x)

Cross multiply


x^(2)=pz

Hence proved.


In the diagram abc=adb=90, ad=p and dc=q. Use similar triangles to show that x2=pz-example-1
User Zhenglei
by
7.9k points

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