Question

A certain shade of blue has a frequency of 7.29 × 1014 hz. What is the energy of exactly one photon of this light?

Answer 1

To solve this problem, we're going to have to use the equation: E=hv

This equation tells us that the energy of a particle of light (E), called a photon, is proportional to its frequency (v), by a constant factor (h). That constant (Planck's constant) we know to be 6.626 × 10^-34 J·s. So, we can plug in the frequency and Planck's constant to solve for the energy (E).

E=( 6.626 × 10^-34 J·s)(7.29 × 10^14 hz)

E= 4.830354 × 10^-19

Round to 3 significant figures, and you're done!

E= 4.83 × 10^-19

Answer 2

`4.83* 10^(-19) J` is the energy of exactly one photon of this light.

Step-by-step explanation:

Frequency of the blue shade light =
`\\u =7.29* 10^(14) Hz`

Energy of the photon is given by Planck's equation = E

`E=h\\u`

h = Planck's constant =
`6.634* 10^(-34) Js`

`E=6.634* 10^(-34) Js* 7.29* 10^(14) s^(-1)`

`E=4.83* 10^(-19) J`

`4.83* 10^(-19) J` is the energy of exactly one photon of this light.