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If a and b are integers and 71 < ab < 76, then all of the following could be the values of b except: (A) 18 (B) 8 (C) 12 (D) 7 (E) 5

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We are given that

a and b are integers and 71 < ab < 76

We will check each options

option-A:

b=18

we can plug it


71<a(18)<76

we can divide both sides by 18


(71)/(18) <b<(76)/(18)

now, we can simplify it


3.944<a<4.222

Since, 'a' is a integer

so, a=4 lies on interval

so, this interval is true

so, this is FALSE

option-B:

b=8

we can plug it


71<a(8)<76

we can divide both sides by 8


(71)/(8) <b<(76)/(8)

now, we can simplify it


8.875<a<9.5

Since, 'a' is a integer

so, a=9 lies on interval

so, this interval is true

so, this is FALSE

option-C:

b=12

we can plug it


71<a(8)<76

we can divide both sides by 12


(71)/(12) <b<(76)/(12)

now, we can simplify it


5.9166<a<6.333

Since, 'a' is a integer

so, a=6 lies on interval

so, this interval is true

so, this is FALSE

option-D:

b=7

we can plug it


71<a(5)<76

we can divide both sides by 7


(71)/(7) <b<(76)/(7)

now, we can simplify it


10.14285<a<10.857

Since, 'a' is a integer

so, no integer lies on this interval

so, this interval is false

so, this is TRUE

option-E:

b=5

we can plug it


71<a(5)<76

we can divide both sides by 5


(71)/(5) <b<(76)/(5)

now, we can simplify it


14.2<a<15.2

Since, 'a' is a integer

so, a=15

so, this interval is true

so, this is FALSE


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