Question

Collision practice

Running at 2.0 m/s, Bruce, the 45.0-kg quarterback, collides with Biff, the 90.0 kg tackle, who is traveling at 7.0 m/s in the other direction. Upon collision,
Biff wraps up Biff for the tackle. What is the resultant velocity of the players.

V=————— m/s

Answer 1

`v_f=4\:\mathrm{m/s\: in\:Biff's\:direction}`

Step-by-step explanation:

Using the Law of Conservation of Momentum, we can set up the following equation:

`m_2v_2-m_1v_1=m_fv_f`, where
`m_1v_1` is Bruce's momentum and
`m_2v_2`.

Plugging in given values, we get:

`90\cdot7-45\cdot2=(90+45)v_f, \\v_f=(540)/(135)=\fbox{$4\:\mathrm{m/s}$}`.