Question

Seven less than negative two times a number is greater than or equal to 41

Answer 1

`Solution, -2n-7\ge \:41\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-24\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-24]\end{bmatrix}`

`Steps:`

`\mathrm{Add\:}7\mathrm{\:to\:both\:sides}, -2n-7+7\ge \:41+7`

`\mathrm{Simplify}, -2n\ge \:48\\\\`

`\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}, \left(-2n\right)\left(-1\right)\le \:48\left(-1\right)`

`\mathrm{Simplify}, 2n\le \:-48`

`\mathrm{Divide\:both\:sides\:by\:}2, (2n)/(2)\le (-48)/(2)`

`\mathrm{Simplify}, n\le \:-24`

The correct answer is
`n\le \:-24`

I hope this helps!!!