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mary pitches a ball. the initial height is 8 ft and velocity 80 ft per second. when will the ball hit the ground?

1 Answer

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Initial velocity of the ball (u) = 80 ft/ sec

Final velocity of the ball after reaching the ground (v) = 0

Distance covered by the ball to reach the ground (s) = 8 ft

Let "a" be the acceleration of the ball.

We know,
2as=v^(2)-u^(2)


2a(8)=0-80^(2)=-6400


a=-(6400)/(16)


a=-400ft/s^(2)

Let "t" be the time required to reach the ground.

We know,


v=u+at


t=(v-u)/(a)


t=(0-80)/(-400)


t=0.2s

The ball will hit the ground in 0.2 second.

User KlajdPaja
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