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A moving rope (parallel to the slope) is used to pull skiers up the mountain. If the slope of the hill is 37" and friction is negligible, what force must the rope provide to pull a 500 N person up the hill at a constant rate?

User Nolan
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1 Answer

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Since rope is parallel to the inclined plane so here we can say that net force parallel to the person which is pulling upwards must counterbalance the component of weight of the person.

Now here we will do the components of the weight of the person

given that weight of the person = 500 N

now its components are


W_x = 500 cos37


W_y = 500 sin37

now here as we can say that one of the component is balanced here by the normal force perpendicular to plane

while the other component of the weight is balanced by the force applied on the rope

So here the force applied on the rope will be given as


F = W_y = 500 sin37


F = 300 N

so it apply 300 N force along the inclined plane

User ThomasW
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