Question

What is the mass of a sample of aluminum that absorbs 596 J of heat when the temperature is raised from 30.0°C to 100.1°C? Specific heat of aluminum = 0.900 J/g oC

Answer 1

Answer is: the mass of a sample of aluminum is 9.45 grams.

ΔT = 100.1°C - 30.0°C.

ΔT = 70.1°C.; change in temperature of a sample of aluminium.

Cp(Al) = 0.900 J/g·°C; specific heat capacity for aluminium.

Q = 596 J; heat absorbed.

Q = m(Al) · ΔT · Cp(Al).

m(Al) = Q ÷ (ΔT · Cp(Al)).

m(Al) = 596 J ÷ (70.1°C · 0.900 J/g·°C).

m(Al) = 9.45 g; mass of aluminium sample.