How much heat is absorbed when 100.0g of ice is melted?

asked Feb 26, 2019 119k views

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The quantity of heat absorbed is 33.4 kJ.

ΔH_fus = 334 J·g⁻¹

q = mΔH_fus = 100.0 g × 334 J·g⁻¹ = 3.34 × 10⁴ J = 33.4 kJ

Amar answered Mar 3, 2019

by Amar

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