Question

G(x)=(x^2+1)(3x-5) what is the value of g(4)?

Answer 1

g(x) = x^2 + 1(3x - 5)

Replace all x's with 4.

g(4) = 4^2 + 1(3 * 4 - 5)

g(4) = 16 + 1(12 - 5)

g(4) = 17(7)

g(4) = 119 (This is your answer.)