Question

Help? *****20 Points*****

Answer 1

1. A

2. C

3. C

4. D

5. B

Answer 2

`1.\\(-1.5)^0=1\\/\text{for any real numbers not equal 0 we have}\ a^0=1/\\\\2.\\3g^(-2)b^2=3\cdot(1)/(g^2)\cdot b^2=(3b^2)/(g^2)\\\\/a^(-n)=(1)/(a^n)/\\\\3.\\(3)/(g^(-2)h^3)=(3)/((1)/(g^2)\cdot h^3)=(3)/(h^3)\cdot(g^2)/(1)=(3g^2)/(h^3)\\\\4.\\2x^(-2)y^(-2)=2\cdot(1)/(x^2)\cdot(1)/(y^2)=(2)/(x^2y^2)\\\\\text{substitute x = 3 and y = -2}\\\\(2)/(3^2\cdot(-2)^2)=(\\ot2^1)/(9\cdot\\ot4_2)=(1)/(9\cdot2)=(1)/(18)\\`

`(1)/(2^(-2)x^(-3)y^5)=(1)/((1)/(2^2)\cdot(1)/(x^3)\cdot y^5)=(1)/(y^5)\cdot(2^2)/(1)\cdot(x^3)/(1)=(2^2x^3)/(y^5)\\\\\text{substitute x = 2 and y = -4}\\\\(2^2(2^3))/((-4)^5)=(2^(2+3))/((-4)^5)=(2^5)/((-4)^5)=\left((2)/(-4)\right)^5=\left(-(1)/(2)\right)^5=-(1)/(32)\\\\/a^n\cdot a^m=a^(n+m);\ \left((a)/(b)\right)^n=(a^n)/(b^n)/`