(2x^2+4x-9)-(3x^2-2x+10) show work

asked Nov 26, 2019 145k views

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$Solution, \left(2x^2+4x-9\right)-\left(3x^2-2x+10\right)=-x^2+6x-19$

Steps:

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a, =2x^2+4x-9-\left(3x^2-2x+10\right)$

$-\left(3x^2-2x+10\right):\quad -3x^2+2x-10\\$

=2x^2+4x-9-3x^2+2x-10
$\mathrm{Simplify}\:2x^2+4x-9-3x^2+2x-10:\quad -x^2+6x-19, =-x^2+6x-19$

Cradam answered Dec 2, 2019

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