Question

What is the equation of the line with a slope of 3/4 that goes through the point (4,1) in slope-intercept form ?

Answer 1

The slope-point form of a line:

`y-y_0=m(x-x_0)`

We have

`m=(3)/(4)\\\\(4,\ 1)\to x_0=4,\ y_0=1`

Substitute:

`y-1=(3)/(4)(x-4)`

The slope-intercept form:

`y=mx+b`

Solve for y:

`y-1=(3)/(4)(x-4)\qquad|\text{use distributive property}\\\\y-1=(3)/(4)x-3\qquad|\text{add 1 to both sides}\\\\y=(3)/(4)x-2`

Answer: D.