Question

Uh need a bit of help with this question

Answer 1

a^m a^n = a^{m+n}

So here

13^8 \times 13 ^{-4} = 13^{8+ -4}= 13^4

Answer: C

Answer 2

When we multiply two powers of a common base, we add the exponents. That's the familiar rule

`a^m a^n = a^(m+n)`

So here

`13^8 * 13 ^(-4) = 13^(8+ -4)= 13^4`

Answer: C