Register
What is the empirical formula of a compound that is 14 g calcium, 11g oxygen, and 0.7 g hydrogen
223k views
5 votes
What is the empirical formula of a compound that is 14 g calcium, 11g oxygen, and 0.7 g hydrogen

User Mathieu Renda
by
9.1k points

1 Answer

3 votes
CaO2H2

convert to moles, divide all by smallest mole mass, multiply til whole

14 g Ca ÷ 40.08 = .35 mol
11 g O ÷ 16 = .69 mol
.7 g H ÷ 1.008 = .69 mol

.35 ÷ .35 = 1
.69 ÷ .35 = 2
.69 ÷ .35 = 2

CaO2H2
User Xfeep
by
8.6k points
← Prev Question Next Question →

Related questions

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

Compare and contrast an electric generator and a battery??
How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
Can someone complete the chemical reactions, or write which one do not occur, and provide tehir types? *c2h4+h2o *c3h8 + hcl *c2h2+br2 *c4h10+br2 *c3h6+br2
As an object’s temperature increases, the ____________________ at which it radiates energy increases.
Why is gold preferred as a superior metal over silver and bronze?
Link Copied!