92.9k views
0 votes
Can someone explain this differentiation question to me? I can differentiate but then I'm not sure what I am doing

Can someone explain this differentiation question to me? I can differentiate but then-example-1

1 Answer

5 votes

note that gradient =
(dy)/(dx) at x = a

calculate
(dy)/(dx) for each pair of functions and compare gradient

(a)


(dy)/(dx) = 2x and
(dy)/(dx) = - 1

at x = 4 : gradient = 8 and - 1 : 8 > - 1

(b)


(dy)/(dx) = 2x + 3 and
(dy)/(dx) = - 2

at x = 2 : gradient = 7 and - 2 and 7 > - 2

(c)


(dy)/(dx) = 4x + 13 and
(dy)/(dx) = 2

at x = - 7 : gradient = - 15 and 2 and 2 > - 15

(d)


(dy)/(dx) = 6x - 5 and
(dy)/(dx) = 2x - 2

at x = - 1 : gradient = - 11 and - 4 and - 4 > - 11

(e)

y = √x =
x^{(1)/(2) }


(dy)/(dx) = 1/(2√x) and
(dy)/(dx) = 2

at x = 9 : gradient =
(1)/(6) and 2 and 2 >
(1)/(6)


User Jonah Graham
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories