Solution: We are given a population follows a normal distribution with Mean
and standard deviation
![\sigma=25](https://img.qammunity.org/2019/formulas/mathematics/high-school/dmuox6hj3gup2pbc81bofn39vbom3zrcaj.png)
According to central limit theorem, if we have a population with mean
and standard deviation
and take large samples from the population, then the distribution of samples means will be approximately normally distributed with mean and standard deviation given below:
![\sigma_{\bar{x}}=(\sigma)/(√(n))](https://img.qammunity.org/2019/formulas/mathematics/high-school/cfjw4h032yc1fcdlkv2eih98uoar9a5l3u.png)
Therefore, for the given example the distribution of sample means will be approximately normal with mean and standard deviation given below:
![\mu_{\bar{x}}=\mu=64](https://img.qammunity.org/2019/formulas/mathematics/high-school/i9if37hvm4lirsrod5hqrgvk53daerk5ek.png)
rounded to 2 decimal places.