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PLEASE HELP ME!!!!!!!!!

PLEASE HELP ME!!!!!!!!!-example-1
User Thurston
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1 Answer

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Starting with the 120° angle, relative to that, we have

... I is vertical so equal, 120°

... J, K are linear angles, so supplementary, 60°

... Q is same-side internal, so supplementary, 60°

... P is alternate internal, so equal, 120°.

Starting with the 40° angle, relative to that, we have

... M is vertical, so equal, 40°

... N, O are linear angles, so supplementary, 140°

... G is corresponding, so equal, 40°

... E is alternate external, so equal, 40°

... F is same-side external, so supplementary, 140°

H is an external angle to the triangle LMQ. Angles M and Q are opposite internal angles, so H is their sum, 40° +60° = 100°. (H is also opposite internal angles G and K, which have the same sum.)

L is a linear angle with H, so supplementary, 80°.

In summary,

... E 40°, F 140°, G 40°, H 100°, I 120°, J 60°, K 60°, L 80°, M 40°, N 140°, O 140°, P 120°, Q 60°

User Makerj
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