Let's break down the problem step by step.
The sum of 4 times a larger integer can be summarized as:
4x
9 times a smaller integer can be summarized as:
9y
We know that we're adding the two expressions because the beginning of the problem has sum. We also know the sum is 3.
So, we get:
4x + 9y = 3
Continuing with the problem, we have the difference between 8 times the larger
8x
We also have 3 times the smaller
3y
This part of the problem mentions the difference between these expressions so we subtract and we know the difference is 27.
8x - 3y = 27
Now, we have both equations so we can solve for either x or y.
4x + 9y = 3
8x - 3y = 27
It's easier to multiply the 4x equation by 2 to have both equations resulting in 8x
(4x + 9y = 3) * 2
We get:
8x +18y = 6
So, we now have:
8x + 18y = 6
8x - 3y = 27
We can subtract the x to get y by itself. We get:
21y = -21
Solve for y and we get:
y = -1
Since we know what y is, we can plug that in and solve for x. It doesn't matter which equation you plug y back in. I'm gonna use the second equation.
8x - 3y = 27
8x - 3 (-1) = 27
8x + 3 = 27
8x = 24
x = 3
So, we now know that
y = -1
x = 3
Hope this helped! If you have any questions then please leave a comment!