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Picture is question i need help as soon as possible

Picture is question i need help as soon as possible-example-1
User Brennon
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1 Answer

11 votes
11 votes

Answer:

32.7 m

Step-by-step explanation:

If it is in the air for 5.16 s the highest point is at one-half of this time

= 5.16/2 = 2.58 s <====== at this point velocity = zero

vf = vi + at

0 = vi - 9.8 (2.58) shows vi = 25.3 m/s

d = vi t + 1/2 at^2

= 25.3 (2.58) - 1/2 (9.8) (2.58^2 ) = max height = 32.7 meters

User Leenremm
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