Question

How much energy is required to completely boil away 225 kg of water?

Hv = 226,000 J/kg
Hf = 334,000 J/kg

Answer 1

E = 50850[kJ]

Step-by-step explanation:

To boil the water we must use the latent heat of vaporization. Also we need to multiply this value by the mass of the water.

`E=m*H_(v)`

Where:

E = energy produced by heat [J]

m = mass = 225 [kg]

Hv = 226000 [J/kg]

`E = 225*226000\\E = 50850000 [J]\\E=50850[kJ]`