Question

Question 5

Solve the following system of equations by using the substitution method.
y = 6x – 11
-2x – 3y = -7

(1, 2)

(2, 1)

(-3, 1)

(2, 4)

Answer 1

answer is (2,1)

y = 6x – 11

-2x – 3y = -7

Substitute 6x - 11 for y in the second equation

-2x – 3(6x-11) = -7

-2x – 18x +33 = -7

-20x + 33 = -7

Now subtract 33 on both sides

-20x = -7 - 33

-20x = -40 ( divide by -20 on both sides)

x= 2

We know y = 6x -11

Plug in 2 for x and find out y

y = 6(2) -11= 12 -11 = 1

So answer is (2,1)